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2(3x-5)+16=3+5(2x-15)
We move all terms to the left:
2(3x-5)+16-(3+5(2x-15))=0
We multiply parentheses
6x-(3+5(2x-15))-10+16=0
We calculate terms in parentheses: -(3+5(2x-15)), so:We add all the numbers together, and all the variables
3+5(2x-15)
determiningTheFunctionDomain 5(2x-15)+3
We multiply parentheses
10x-75+3
We add all the numbers together, and all the variables
10x-72
Back to the equation:
-(10x-72)
6x-(10x-72)+6=0
We get rid of parentheses
6x-10x+72+6=0
We add all the numbers together, and all the variables
-4x+78=0
We move all terms containing x to the left, all other terms to the right
-4x=-78
x=-78/-4
x=19+1/2
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