2(3x-5)+1=(-4+5)+(7x-8)

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Solution for 2(3x-5)+1=(-4+5)+(7x-8) equation: 



2(3x-5)+1=(-4+5)+(7x-8)

We move all terms to the left:

2(3x-5)+1-((-4+5)+(7x-8))=0

We add all the numbers together, and all the variables

2(3x-5)-(1+(7x-8))+1=0

We multiply parentheses

6x-(1+(7x-8))-10+1=0



We calculate terms in parentheses: -(1+(7x-8)), so:

1+(7x-8)

determiningTheFunctionDomain
(7x-8)+1

We get rid of parentheses

7x-8+1

We add all the numbers together, and all the variables

7x-7

Back to the equation:

-(7x-7)



We add all the numbers together, and all the variables

6x-(7x-7)-9=0

We get rid of parentheses

6x-7x+7-9=0

We add all the numbers together, and all the variables

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2

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