2(3x-5)+1=-4x+5)+(7x-8)

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Solution for 2(3x-5)+1=-4x+5)+(7x-8) equation: 



2(3x-5)+1=-4x+5)+(7x-8)

We move all terms to the left:

2(3x-5)+1-(-4x+5)+(7x-8))=0

We multiply parentheses

6x-(-4x+5)+(7x-8))+1-10=0

We get rid of parentheses

6x+4x+(7x-8))+1-10-5=0

We add all the numbers together, and all the variables

10x+(7x-8))+1-10-5=0

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