2(3x-5)+7x-4=3(4x-7)+8

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Solution for 2(3x-5)+7x-4=3(4x-7)+8 equation: 



2(3x-5)+7x-4=3(4x-7)+8

We move all terms to the left:

2(3x-5)+7x-4-(3(4x-7)+8)=0

We add all the numbers together, and all the variables

7x+2(3x-5)-(3(4x-7)+8)-4=0

We multiply parentheses

7x+6x-(3(4x-7)+8)-10-4=0



We calculate terms in parentheses: -(3(4x-7)+8), so:

3(4x-7)+8

We multiply parentheses

12x-21+8

We add all the numbers together, and all the variables

12x-13

Back to the equation:

-(12x-13)



We add all the numbers together, and all the variables

13x-(12x-13)-14=0

We get rid of parentheses

13x-12x+13-14=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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