2(3x-5)-1=-7(x-1)+x+4

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Solution for 2(3x-5)-1=-7(x-1)+x+4 equation: 



2(3x-5)-1=-7(x-1)+x+4

We move all terms to the left:

2(3x-5)-1-(-7(x-1)+x+4)=0

We multiply parentheses

6x-(-7(x-1)+x+4)-10-1=0



We calculate terms in parentheses: -(-7(x-1)+x+4), so:

-7(x-1)+x+4

We add all the numbers together, and all the variables

x-7(x-1)+4

We multiply parentheses

x-7x+7+4

We add all the numbers together, and all the variables

-6x+11

Back to the equation:

-(-6x+11)



We add all the numbers together, and all the variables

6x-(-6x+11)-11=0

We get rid of parentheses

6x+6x-11-11=0

We add all the numbers together, and all the variables

12x-22=0

We move all terms containing x to the left, all other terms to the right

12x=22

x=22/12

x=1+5/6

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