2(3x-5)-1=7(x-1)+x+4

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Solution for 2(3x-5)-1=7(x-1)+x+4 equation: 



2(3x-5)-1=7(x-1)+x+4

We move all terms to the left:

2(3x-5)-1-(7(x-1)+x+4)=0

We multiply parentheses

6x-(7(x-1)+x+4)-10-1=0



We calculate terms in parentheses: -(7(x-1)+x+4), so:

7(x-1)+x+4

We add all the numbers together, and all the variables

x+7(x-1)+4

We multiply parentheses

x+7x-7+4

We add all the numbers together, and all the variables

8x-3

Back to the equation:

-(8x-3)



We add all the numbers together, and all the variables

6x-(8x-3)-11=0

We get rid of parentheses

6x-8x+3-11=0

We add all the numbers together, and all the variables

-2x-8=0

We move all terms containing x to the left, all other terms to the right

-2x=8

x=8/-2

x=-4

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