2(3x-5)-6=3(x+2)-5

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Solution for 2(3x-5)-6=3(x+2)-5 equation: 



2(3x-5)-6=3(x+2)-5

We move all terms to the left:

2(3x-5)-6-(3(x+2)-5)=0

We multiply parentheses

6x-(3(x+2)-5)-10-6=0



We calculate terms in parentheses: -(3(x+2)-5), so:

3(x+2)-5

We multiply parentheses

3x+6-5

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

6x-(3x+1)-16=0

We get rid of parentheses

6x-3x-1-16=0

We add all the numbers together, and all the variables

3x-17=0

We move all terms containing x to the left, all other terms to the right

3x=17

x=17/3

x=5+2/3

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