2(3x-5)=(2x+3)-7

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Solution for 2(3x-5)=(2x+3)-7 equation: 



2(3x-5)=(2x+3)-7

We move all terms to the left:

2(3x-5)-((2x+3)-7)=0

We multiply parentheses

6x-((2x+3)-7)-10=0



We calculate terms in parentheses: -((2x+3)-7), so:

(2x+3)-7

We get rid of parentheses

2x+3-7

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We get rid of parentheses

6x-2x+4-10=0

We add all the numbers together, and all the variables

4x-6=0

We move all terms containing x to the left, all other terms to the right

4x=6

x=6/4

x=1+1/2

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