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2(3x-5)=-5(1-x)
We move all terms to the left:
2(3x-5)-(-5(1-x))=0
We add all the numbers together, and all the variables
2(3x-5)-(-5(-1x+1))=0
We multiply parentheses
6x-(-5(-1x+1))-10=0
We calculate terms in parentheses: -(-5(-1x+1)), so:We get rid of parentheses
-5(-1x+1)
We multiply parentheses
5x-5
Back to the equation:
-(5x-5)
6x-5x+5-10=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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