2(3x-5)=10x-38

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Solution for 2(3x-5)=10x-38 equation: 



2(3x-5)=10x-38

We move all terms to the left:

2(3x-5)-(10x-38)=0

We multiply parentheses

6x-(10x-38)-10=0

We get rid of parentheses

6x-10x+38-10=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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