2(3x-5)=2(6x+10)

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Solution for 2(3x-5)=2(6x+10) equation: 



2(3x-5)=2(6x+10)

We move all terms to the left:

2(3x-5)-(2(6x+10))=0

We multiply parentheses

6x-(2(6x+10))-10=0



We calculate terms in parentheses: -(2(6x+10)), so:

2(6x+10)

We multiply parentheses

12x+20

Back to the equation:

-(12x+20)



We get rid of parentheses

6x-12x-20-10=0

We add all the numbers together, and all the variables

-6x-30=0

We move all terms containing x to the left, all other terms to the right

-6x=30

x=30/-6

x=-5

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