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2(3x-5)=2/3(9x-15)
We move all terms to the left:
2(3x-5)-(2/3(9x-15))=0
Domain of the equation: 3(9x-15))!=0We multiply parentheses
x∈R
6x-(2/3(9x-15))-10=0
We multiply all the terms by the denominator
6x*3(9x-15))-(2-10*3(9x-15))=0
Wy multiply elements
18x^2(9-30x(9=0
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