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2(3x-5)=3(2x+10)
We move all terms to the left:
2(3x-5)-(3(2x+10))=0
We multiply parentheses
6x-(3(2x+10))-10=0
We calculate terms in parentheses: -(3(2x+10)), so:We get rid of parentheses
3(2x+10)
We multiply parentheses
6x+30
Back to the equation:
-(6x+30)
6x-6x-30-10=0
We add all the numbers together, and all the variables
-40!=0
There is no solution for this equation
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