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2(3x-5)=3(x+14)
We move all terms to the left:
2(3x-5)-(3(x+14))=0
We multiply parentheses
6x-(3(x+14))-10=0
We calculate terms in parentheses: -(3(x+14)), so:We get rid of parentheses
3(x+14)
We multiply parentheses
3x+42
Back to the equation:
-(3x+42)
6x-3x-42-10=0
We add all the numbers together, and all the variables
3x-52=0
We move all terms containing x to the left, all other terms to the right
3x=52
x=52/3
x=17+1/3
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