2(3x-5)=3x(2x+3)

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Solution for 2(3x-5)=3x(2x+3) equation: 



2(3x-5)=3x(2x+3)

We move all terms to the left:

2(3x-5)-(3x(2x+3))=0

We multiply parentheses

6x-(3x(2x+3))-10=0



We calculate terms in parentheses: -(3x(2x+3)), so:

3x(2x+3)

We multiply parentheses

6x^2+9x

Back to the equation:

-(6x^2+9x)



We get rid of parentheses

-6x^2+6x-9x-10=0

We add all the numbers together, and all the variables

-6x^2-3x-10=0

a = -6; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·(-6)·(-10)
Δ = -231
Delta is less than zero, so there is no solution for the equation

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