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2(3x-5)=4(2x+1)
We move all terms to the left:
2(3x-5)-(4(2x+1))=0
We multiply parentheses
6x-(4(2x+1))-10=0
We calculate terms in parentheses: -(4(2x+1)), so:We get rid of parentheses
4(2x+1)
We multiply parentheses
8x+4
Back to the equation:
-(8x+4)
6x-8x-4-10=0
We add all the numbers together, and all the variables
-2x-14=0
We move all terms containing x to the left, all other terms to the right
-2x=14
x=14/-2
x=-7
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