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2(3x-5)=4(2x-3)
We move all terms to the left:
2(3x-5)-(4(2x-3))=0
We multiply parentheses
6x-(4(2x-3))-10=0
We calculate terms in parentheses: -(4(2x-3)), so:We get rid of parentheses
4(2x-3)
We multiply parentheses
8x-12
Back to the equation:
-(8x-12)
6x-8x+12-10=0
We add all the numbers together, and all the variables
-2x+2=0
We move all terms containing x to the left, all other terms to the right
-2x=-2
x=-2/-2
x=1
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