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2(3x-5)=4(x+2)-19
We move all terms to the left:
2(3x-5)-(4(x+2)-19)=0
We multiply parentheses
6x-(4(x+2)-19)-10=0
We calculate terms in parentheses: -(4(x+2)-19), so:We get rid of parentheses
4(x+2)-19
We multiply parentheses
4x+8-19
We add all the numbers together, and all the variables
4x-11
Back to the equation:
-(4x-11)
6x-4x+11-10=0
We add all the numbers together, and all the variables
2x+1=0
We move all terms containing x to the left, all other terms to the right
2x=-1
x=-1/2
x=-1/2
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