2(3x-5)=492x=80

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Solution for 2(3x-5)=492x=80 equation: 



2(3x-5)=492x=80

We move all terms to the left:

2(3x-5)-(492x)=0

We add all the numbers together, and all the variables

-492x+2(3x-5)=0

We multiply parentheses

-492x+6x-10=0

We add all the numbers together, and all the variables

-486x-10=0

We move all terms containing x to the left, all other terms to the right

-486x=10

x=10/-486

x=-5/243

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