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2(3x-6)=3(2x-4)*
We move all terms to the left:
2(3x-6)-(3(2x-4)*)=0
We multiply parentheses
6x-(3(2x-4)*)-12=0
We calculate terms in parentheses: -(3(2x-4)*), so:We get rid of parentheses
3(2x-4)*
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
6x-6x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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