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2(3x-7)-2=2(x-3)+2
We move all terms to the left:
2(3x-7)-2-(2(x-3)+2)=0
We multiply parentheses
6x-(2(x-3)+2)-14-2=0
We calculate terms in parentheses: -(2(x-3)+2), so:We add all the numbers together, and all the variables
2(x-3)+2
We multiply parentheses
2x-6+2
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
6x-(2x-4)-16=0
We get rid of parentheses
6x-2x+4-16=0
We add all the numbers together, and all the variables
4x-12=0
We move all terms containing x to the left, all other terms to the right
4x=12
x=12/4
x=3
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