2(3x-7)-4=2(x-4)+26

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Solution for 2(3x-7)-4=2(x-4)+26 equation: 



2(3x-7)-4=2(x-4)+26

We move all terms to the left:

2(3x-7)-4-(2(x-4)+26)=0

We multiply parentheses

6x-(2(x-4)+26)-14-4=0



We calculate terms in parentheses: -(2(x-4)+26), so:

2(x-4)+26

We multiply parentheses

2x-8+26

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

6x-(2x+18)-18=0

We get rid of parentheses

6x-2x-18-18=0

We add all the numbers together, and all the variables

4x-36=0

We move all terms containing x to the left, all other terms to the right

4x=36

x=36/4

x=9

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