2(3x-7)-5=2(x-4)+17

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Solution for 2(3x-7)-5=2(x-4)+17 equation: 



2(3x-7)-5=2(x-4)+17

We move all terms to the left:

2(3x-7)-5-(2(x-4)+17)=0

We multiply parentheses

6x-(2(x-4)+17)-14-5=0



We calculate terms in parentheses: -(2(x-4)+17), so:

2(x-4)+17

We multiply parentheses

2x-8+17

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We add all the numbers together, and all the variables

6x-(2x+9)-19=0

We get rid of parentheses

6x-2x-9-19=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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