2(3x-8)+6=4x-3(2-2x)

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Solution for 2(3x-8)+6=4x-3(2-2x) equation:



2(3x-8)+6=4x-3(2-2x)
We move all terms to the left:
2(3x-8)+6-(4x-3(2-2x))=0
We add all the numbers together, and all the variables
2(3x-8)-(4x-3(-2x+2))+6=0
We multiply parentheses
6x-(4x-3(-2x+2))-16+6=0
We calculate terms in parentheses: -(4x-3(-2x+2)), so:
4x-3(-2x+2)
We multiply parentheses
4x+6x-6
We add all the numbers together, and all the variables
10x-6
Back to the equation:
-(10x-6)
We add all the numbers together, and all the variables
6x-(10x-6)-10=0
We get rid of parentheses
6x-10x+6-10=0
We add all the numbers together, and all the variables
-4x-4=0
We move all terms containing x to the left, all other terms to the right
-4x=4
x=4/-4
x=-1

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