2(3x-8)+7=4(x-2)+1

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Solution for 2(3x-8)+7=4(x-2)+1 equation: 



2(3x-8)+7=4(x-2)+1

We move all terms to the left:

2(3x-8)+7-(4(x-2)+1)=0

We multiply parentheses

6x-(4(x-2)+1)-16+7=0



We calculate terms in parentheses: -(4(x-2)+1), so:

4(x-2)+1

We multiply parentheses

4x-8+1

We add all the numbers together, and all the variables

4x-7

Back to the equation:

-(4x-7)



We add all the numbers together, and all the variables

6x-(4x-7)-9=0

We get rid of parentheses

6x-4x+7-9=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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