2(3x-8)-5+7x=-8-(2-8)+8x

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Solution for 2(3x-8)-5+7x=-8-(2-8)+8x equation: 



2(3x-8)-5+7x=-8-(2-8)+8x

We move all terms to the left:

2(3x-8)-5+7x-(-8-(2-8)+8x)=0

We add all the numbers together, and all the variables

2(3x-8)+7x-(-8-(-6)+8x)-5=0

We add all the numbers together, and all the variables

7x+2(3x-8)-(-8-(-6)+8x)-5=0

We multiply parentheses

7x+6x-(-8-(-6)+8x)-16-5=0



We calculate terms in parentheses: -(-8-(-6)+8x), so:

-8-(-6)+8x

determiningTheFunctionDomain
8x-8-(-6)

We add all the numbers together, and all the variables

8x-2

Back to the equation:

-(8x-2)



We add all the numbers together, and all the variables

13x-(8x-2)-21=0

We get rid of parentheses

13x-8x+2-21=0

We add all the numbers together, and all the variables

5x-19=0

We move all terms containing x to the left, all other terms to the right

5x=19

x=19/5

x=3+4/5

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