2(3x-8)=10x+20-4-4x

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Solution for 2(3x-8)=10x+20-4-4x equation: 



2(3x-8)=10x+20-4-4x

We move all terms to the left:

2(3x-8)-(10x+20-4-4x)=0

We add all the numbers together, and all the variables

2(3x-8)-(6x+16)=0

We multiply parentheses

6x-(6x+16)-16=0

We get rid of parentheses

6x-6x-16-16=0

We add all the numbers together, and all the variables

-32!=0

There is no solution for this equation

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