2(3x-9)+12=3(10+x)

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Solution for 2(3x-9)+12=3(10+x) equation: 



2(3x-9)+12=3(10+x)

We move all terms to the left:

2(3x-9)+12-(3(10+x))=0

We add all the numbers together, and all the variables

2(3x-9)-(3(x+10))+12=0

We multiply parentheses

6x-(3(x+10))-18+12=0



We calculate terms in parentheses: -(3(x+10)), so:

3(x+10)

We multiply parentheses

3x+30

Back to the equation:

-(3x+30)



We add all the numbers together, and all the variables

6x-(3x+30)-6=0

We get rid of parentheses

6x-3x-30-6=0

We add all the numbers together, and all the variables

3x-36=0

We move all terms containing x to the left, all other terms to the right

3x=36

x=36/3

x=12

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