2(3x-9)=(6x-18/2)2

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Solution for 2(3x-9)=(6x-18/2)2 equation:


x in (-oo:+oo)

2*(3*x-9) = (6*x-(18/2))^2 // - (6*x-(18/2))^2

2*(3*x-9)-(6*x-(18/2))^2 = 0

2*(3*x-9)-(6*x-9)^2 = 0

2*(3*x-9)-1*(6*x-9)^2 = 0

2*(3*x-9)-1*(6*x-9)^2 = 0

114*x-36*x^2-99 = 0

114*x-36*x^2-99 = 0

3*(38*x-12*x^2-33) = 0

38*x-12*x^2-33 = 0

DELTA = 38^2-(-33*(-12)*4)

DELTA = -140

DELTA < 0

3 = 0

3 = 0

x belongs to the empty set

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