2(3x-9)=-2(-x+1)+9x

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Solution for 2(3x-9)=-2(-x+1)+9x equation: 



2(3x-9)=-2(-x+1)+9x

We move all terms to the left:

2(3x-9)-(-2(-x+1)+9x)=0

We add all the numbers together, and all the variables

2(3x-9)-(-2(-1x+1)+9x)=0

We multiply parentheses

6x-(-2(-1x+1)+9x)-18=0



We calculate terms in parentheses: -(-2(-1x+1)+9x), so:

-2(-1x+1)+9x

We add all the numbers together, and all the variables

9x-2(-1x+1)

We multiply parentheses

9x+2x-2

We add all the numbers together, and all the variables

11x-2

Back to the equation:

-(11x-2)



We get rid of parentheses

6x-11x+2-18=0

We add all the numbers together, and all the variables

-5x-16=0

We move all terms containing x to the left, all other terms to the right

-5x=16

x=16/-5

x=-3+1/5

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