2(3x-9)=-2(x+1)+9x

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Solution for 2(3x-9)=-2(x+1)+9x equation: 



2(3x-9)=-2(x+1)+9x

We move all terms to the left:

2(3x-9)-(-2(x+1)+9x)=0

We multiply parentheses

6x-(-2(x+1)+9x)-18=0



We calculate terms in parentheses: -(-2(x+1)+9x), so:

-2(x+1)+9x

We add all the numbers together, and all the variables

9x-2(x+1)

We multiply parentheses

9x-2x-2

We add all the numbers together, and all the variables

7x-2

Back to the equation:

-(7x-2)



We get rid of parentheses

6x-7x+2-18=0

We add all the numbers together, and all the variables

-1x-16=0

We move all terms containing x to the left, all other terms to the right

-x=16

x=16/-1

x=-16

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