2(3x2)=18

Solution for 2(3x2)=18 equation:

2(3x^2)=18

We move all terms to the left:

2(3x^2)-(18)=0

a = 23; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·23·(-18)
Δ = 1656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1656}=\sqrt{36*46}=\sqrt{36}*\sqrt{46}=6\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{46}}{2*23}=\frac{0-6\sqrt{46}}{46}
=-\frac{6\sqrt{46}}{46}
=-\frac{3\sqrt{46}}{23}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{46}}{2*23}=\frac{0+6\sqrt{46}}{46}
=\frac{6\sqrt{46}}{46}
=\frac{3\sqrt{46}}{23}
$