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2(3x^2x)3(x+4)=7x+18
We move all terms to the left:
2(3x^2x)3(x+4)-(7x+18)=0
We get rid of parentheses
23x^2x3(x+4)-7x-18=0
We move all terms containing x to the left, all other terms to the right
23x^2x3(x+4)-7x=18
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