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2(3y)-25=(4y/2)
We move all terms to the left:
2(3y)-25-((4y/2))=0
We add all the numbers together, and all the variables
23y-((+4y/2))-25=0
We multiply all the terms by the denominator
23y*2))-((+4y-25*2))=0
We add all the numbers together, and all the variables
23y*2))-((4y-50))=0
We add all the numbers together, and all the variables
23y*2))-((4y=0
Wy multiply elements
46y^2=0
a = 46; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·46·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{92}=0$
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