2(3y+-7)=16

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Solution for 2(3y+-7)=16 equation: 



2(3y+-7)=16

We move all terms to the left:

2(3y+-7)-(16)=0

We add all the numbers together, and all the variables

2(3y-7)-16=0

We multiply parentheses

6y-14-16=0

We add all the numbers together, and all the variables

6y-30=0

We move all terms containing y to the left, all other terms to the right

6y=30

y=30/6

y=5

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