2(3y+1)-(4y-7)=7-3(3y-2)

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Solution for 2(3y+1)-(4y-7)=7-3(3y-2) equation: 



2(3y+1)-(4y-7)=7-3(3y-2)

We move all terms to the left:

2(3y+1)-(4y-7)-(7-3(3y-2))=0

We multiply parentheses

6y-(4y-7)-(7-3(3y-2))+2=0

We get rid of parentheses

6y-4y-(7-3(3y-2))+7+2=0



We calculate terms in parentheses: -(7-3(3y-2)), so:

7-3(3y-2)

determiningTheFunctionDomain
-3(3y-2)+7

We multiply parentheses

-9y+6+7

We add all the numbers together, and all the variables

-9y+13

Back to the equation:

-(-9y+13)



We add all the numbers together, and all the variables

2y-(-9y+13)+9=0

We get rid of parentheses

2y+9y-13+9=0

We add all the numbers together, and all the variables

11y-4=0

We move all terms containing y to the left, all other terms to the right

11y=4

y=4/11

y=4/11

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