2(3y+1)=25

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Solution for 2(3y+1)=25 equation: 



2(3y+1)=25

We move all terms to the left:

2(3y+1)-(25)=0

We multiply parentheses

6y+2-25=0

We add all the numbers together, and all the variables

6y-23=0

We move all terms containing y to the left, all other terms to the right

6y=23

y=23/6

y=3+5/6

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