2(3y+1)=4(y+5)

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Solution for 2(3y+1)=4(y+5) equation: 



2(3y+1)=4(y+5)

We move all terms to the left:

2(3y+1)-(4(y+5))=0

We multiply parentheses

6y-(4(y+5))+2=0



We calculate terms in parentheses: -(4(y+5)), so:

4(y+5)

We multiply parentheses

4y+20

Back to the equation:

-(4y+20)



We get rid of parentheses

6y-4y-20+2=0

We add all the numbers together, and all the variables

2y-18=0

We move all terms containing y to the left, all other terms to the right

2y=18

y=18/2

y=9

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