2(3y+10)=36

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Solution for 2(3y+10)=36 equation: 



2(3y+10)=36

We move all terms to the left:

2(3y+10)-(36)=0

We multiply parentheses

6y+20-36=0

We add all the numbers together, and all the variables

6y-16=0

We move all terms containing y to the left, all other terms to the right

6y=16

y=16/6

y=2+2/3

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