2(3y+2)+y=11

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Solution for 2(3y+2)+y=11 equation: 



2(3y+2)+y=11

We move all terms to the left:

2(3y+2)+y-(11)=0

We add all the numbers together, and all the variables

y+2(3y+2)-11=0

We multiply parentheses

y+6y+4-11=0

We add all the numbers together, and all the variables

7y-7=0

We move all terms containing y to the left, all other terms to the right

7y=7

y=7/7

y=1

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