2(3y+2)=(12y+8)

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Solution for 2(3y+2)=(12y+8) equation: 



2(3y+2)=(12y+8)

We move all terms to the left:

2(3y+2)-((12y+8))=0

We multiply parentheses

6y-((12y+8))+4=0



We calculate terms in parentheses: -((12y+8)), so:

(12y+8)

We get rid of parentheses

12y+8

Back to the equation:

-(12y+8)



We get rid of parentheses

6y-12y-8+4=0

We add all the numbers together, and all the variables

-6y-4=0

We move all terms containing y to the left, all other terms to the right

-6y=4

y=4/-6

y=-2/3

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