2(3y+3)+3y=15

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Solution for 2(3y+3)+3y=15 equation: 



2(3y+3)+3y=15

We move all terms to the left:

2(3y+3)+3y-(15)=0

We add all the numbers together, and all the variables

3y+2(3y+3)-15=0

We multiply parentheses

3y+6y+6-15=0

We add all the numbers together, and all the variables

9y-9=0

We move all terms containing y to the left, all other terms to the right

9y=9

y=9/9

y=1

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