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2(3y+4)-2(2y-5)=2(4y+2)-2(y+1)
We move all terms to the left:
2(3y+4)-2(2y-5)-(2(4y+2)-2(y+1))=0
We multiply parentheses
6y-4y-(2(4y+2)-2(y+1))+8+10=0
We calculate terms in parentheses: -(2(4y+2)-2(y+1)), so:We add all the numbers together, and all the variables
2(4y+2)-2(y+1)
We multiply parentheses
8y-2y+4-2
We add all the numbers together, and all the variables
6y+2
Back to the equation:
-(6y+2)
2y-(6y+2)+18=0
We get rid of parentheses
2y-6y-2+18=0
We add all the numbers together, and all the variables
-4y+16=0
We move all terms containing y to the left, all other terms to the right
-4y=-16
y=-16/-4
y=+4
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