2(3y+4)-2(2y-5)=2(4y+2)-2(y+1)

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Solution for 2(3y+4)-2(2y-5)=2(4y+2)-2(y+1) equation: 



2(3y+4)-2(2y-5)=2(4y+2)-2(y+1)

We move all terms to the left:

2(3y+4)-2(2y-5)-(2(4y+2)-2(y+1))=0

We multiply parentheses

6y-4y-(2(4y+2)-2(y+1))+8+10=0



We calculate terms in parentheses: -(2(4y+2)-2(y+1)), so:

2(4y+2)-2(y+1)

We multiply parentheses

8y-2y+4-2

We add all the numbers together, and all the variables

6y+2

Back to the equation:

-(6y+2)



We add all the numbers together, and all the variables

2y-(6y+2)+18=0

We get rid of parentheses

2y-6y-2+18=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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