2(3y+4)=3(3y-4)-7y

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Solution for 2(3y+4)=3(3y-4)-7y equation: 



2(3y+4)=3(3y-4)-7y

We move all terms to the left:

2(3y+4)-(3(3y-4)-7y)=0

We multiply parentheses

6y-(3(3y-4)-7y)+8=0



We calculate terms in parentheses: -(3(3y-4)-7y), so:

3(3y-4)-7y

We add all the numbers together, and all the variables

-7y+3(3y-4)

We multiply parentheses

-7y+9y-12

We add all the numbers together, and all the variables

2y-12

Back to the equation:

-(2y-12)



We get rid of parentheses

6y-2y+12+8=0

We add all the numbers together, and all the variables

4y+20=0

We move all terms containing y to the left, all other terms to the right

4y=-20

y=-20/4

y=-5

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