2(3y+4+2)=196

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Solution for 2(3y+4+2)=196 equation: 



2(3y+4+2)=196

We move all terms to the left:

2(3y+4+2)-(196)=0

We add all the numbers together, and all the variables

2(3y+6)-196=0

We multiply parentheses

6y+12-196=0

We add all the numbers together, and all the variables

6y-184=0

We move all terms containing y to the left, all other terms to the right

6y=184

y=184/6

y=30+2/3

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