2(3y+5)+y=3

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Solution for 2(3y+5)+y=3 equation: 



2(3y+5)+y=3

We move all terms to the left:

2(3y+5)+y-(3)=0

We add all the numbers together, and all the variables

y+2(3y+5)-3=0

We multiply parentheses

y+6y+10-3=0

We add all the numbers together, and all the variables

7y+7=0

We move all terms containing y to the left, all other terms to the right

7y=-7

y=-7/7

y=-1

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