2(3y+5)=28+4y

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Solution for 2(3y+5)=28+4y equation:


Simplifying
2(3y + 5) = 28 + 4y

Reorder the terms:
2(5 + 3y) = 28 + 4y
(5 * 2 + 3y * 2) = 28 + 4y
(10 + 6y) = 28 + 4y

Solving
10 + 6y = 28 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
10 + 6y + -4y = 28 + 4y + -4y

Combine like terms: 6y + -4y = 2y
10 + 2y = 28 + 4y + -4y

Combine like terms: 4y + -4y = 0
10 + 2y = 28 + 0
10 + 2y = 28

Add '-10' to each side of the equation.
10 + -10 + 2y = 28 + -10

Combine like terms: 10 + -10 = 0
0 + 2y = 28 + -10
2y = 28 + -10

Combine like terms: 28 + -10 = 18
2y = 18

Divide each side by '2'.
y = 9

Simplifying
y = 9

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