2(3y+5)=5(2y-4)-4y

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Solution for 2(3y+5)=5(2y-4)-4y equation: 


Simplifying
2(3y + 5) = 5(2y + -4) + -4y

Reorder the terms:
2(5 + 3y) = 5(2y + -4) + -4y
(5 * 2 + 3y * 2) = 5(2y + -4) + -4y
(10 + 6y) = 5(2y + -4) + -4y

Reorder the terms:
10 + 6y = 5(-4 + 2y) + -4y
10 + 6y = (-4 * 5 + 2y * 5) + -4y
10 + 6y = (-20 + 10y) + -4y

Combine like terms: 10y + -4y = 6y
10 + 6y = -20 + 6y

Add '-6y' to each side of the equation.
10 + 6y + -6y = -20 + 6y + -6y

Combine like terms: 6y + -6y = 0
10 + 0 = -20 + 6y + -6y
10 = -20 + 6y + -6y

Combine like terms: 6y + -6y = 0
10 = -20 + 0
10 = -20

Solving
10 = -20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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