2(3y+7)=6-(y-1)

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Solution for 2(3y+7)=6-(y-1) equation: 



2(3y+7)=6-(y-1)

We move all terms to the left:

2(3y+7)-(6-(y-1))=0

We multiply parentheses

6y-(6-(y-1))+14=0



We calculate terms in parentheses: -(6-(y-1)), so:

6-(y-1)

determiningTheFunctionDomain
-(y-1)+6

We get rid of parentheses

-y+1+6

We add all the numbers together, and all the variables

-1y+7

Back to the equation:

-(-1y+7)



We get rid of parentheses

6y+1y-7+14=0

We add all the numbers together, and all the variables

7y+7=0

We move all terms containing y to the left, all other terms to the right

7y=-7

y=-7/7

y=-1

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