2(3y-1)+4y=10(2-3y)+38y

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Solution for 2(3y-1)+4y=10(2-3y)+38y equation:


2(3y-1)+4y=10(2-3y)+38y

We simplify the equation to the form, which is simple to understand 
2(3y-1)+4y=10(2-3y)+38y

Reorder the terms in parentheses
+(+6y-2)+4y=10*(2-3y)+38y

Remove unnecessary parentheses
+6y-2+4y=+10+*(+2-3y+)+38y

Reorder the terms in parentheses
+6y-2+4y=+(+20-30y)+38y

Remove unnecessary parentheses
+6y-2+4y=+20-30y+38y

We move all terms containing y to the left and all other terms to the right. 
+6y+4y+30y-38y=+20+2

We simplify left and right side of the equation. 
+2y=+22

We divide both sides of the equation by 2 to get y. 
y=11

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